5y(2y+7)=3(4y-5)

Solution for 5y(2y+7)=3(4y-5) equation:

5y(2y+7)=3(4y-5)

We move all terms to the left:

5y(2y+7)-(3(4y-5))=0

We multiply parentheses

10y^2+35y-(3(4y-5))=0


We calculate terms in parentheses: -(3(4y-5)), so:

3(4y-5)

We multiply parentheses

12y-15

Back to the equation:

-(12y-15)


We get rid of parentheses

10y^2+35y-12y+15=0

We add all the numbers together, and all the variables

10y^2+23y+15=0

a = 10; b = 23; c = +15;
Δ = b2-4ac
Δ = 232-4·10·15
Δ = -71
Delta is less than zero, so there is no solution for the equation