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-1.6x(2)-3.2x+18=0
We add all the numbers together, and all the variables
-1.6x^2-3.2x+18=0
a = -1.6; b = -3.2; c = +18;
Δ = b2-4ac
Δ = -3.22-4·(-1.6)·18
Δ = 125.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.2)-\sqrt{125.44}}{2*-1.6}=\frac{3.2-\sqrt{125.44}}{-3.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.2)+\sqrt{125.44}}{2*-1.6}=\frac{3.2+\sqrt{125.44}}{-3.2} $
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