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5xx(x-3)+(2x+1)=0
We multiply parentheses
5x^2-15x+(2x+1)=0
We get rid of parentheses
5x^2-15x+2x+1=0
We add all the numbers together, and all the variables
5x^2-13x+1=0
a = 5; b = -13; c = +1;
Δ = b2-4ac
Δ = -132-4·5·1
Δ = 149
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{149}}{2*5}=\frac{13-\sqrt{149}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{149}}{2*5}=\frac{13+\sqrt{149}}{10} $
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