28=8z+12

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Solution for 28=8z+12 equation: 



28=8z+12

We move all terms to the left:

28-(8z+12)=0

We get rid of parentheses

-8z-12+28=0

We add all the numbers together, and all the variables

-8z+16=0

We move all terms containing z to the left, all other terms to the right

-8z=-16

z=-16/-8

z=+2

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