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5x=3x(x+2)
We move all terms to the left:
5x-(3x(x+2))=0
We calculate terms in parentheses: -(3x(x+2)), so:We get rid of parentheses
3x(x+2)
We multiply parentheses
3x^2+6x
Back to the equation:
-(3x^2+6x)
-3x^2+5x-6x=0
We add all the numbers together, and all the variables
-3x^2-1x=0
a = -3; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-3)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-3}=\frac{0}{-6} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-3}=\frac{2}{-6} =-1/3 $
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