(10/x)=(20/x-5)

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Solution for (10/x)=(20/x-5) equation:



(10/x)=(20/x-5)
We move all terms to the left:
(10/x)-((20/x-5))=0
Domain of the equation: x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: x-5))!=0
x∈R
We add all the numbers together, and all the variables
(+10/x)-((20/x-5))=0
We get rid of parentheses
10/x-((20/x-5))=0
We calculate fractions
10x/x^2+(-((20*x)/x^2=0
We add all the numbers together, and all the variables
10x/x^2+(-((+20x)/x^2=0
We multiply all the terms by the denominator
10x+(-((+20x)=0
We calculate terms in parentheses: +(-((+20x), so:
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