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5x=1/3x+10
We move all terms to the left:
5x-(1/3x+10)=0
Domain of the equation: 3x+10)!=0We get rid of parentheses
x∈R
5x-1/3x-10=0
We multiply all the terms by the denominator
5x*3x-10*3x-1=0
Wy multiply elements
15x^2-30x-1=0
a = 15; b = -30; c = -1;
Δ = b2-4ac
Δ = -302-4·15·(-1)
Δ = 960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{960}=\sqrt{64*15}=\sqrt{64}*\sqrt{15}=8\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-8\sqrt{15}}{2*15}=\frac{30-8\sqrt{15}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+8\sqrt{15}}{2*15}=\frac{30+8\sqrt{15}}{30} $
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