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5/x+2/2x=6
We move all terms to the left:
5/x+2/2x-(6)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x!=0We calculate fractions
x!=0/2
x!=0
x∈R
10x/2x^2+2x/2x^2-6=0
We multiply all the terms by the denominator
10x+2x-6*2x^2=0
We add all the numbers together, and all the variables
12x-6*2x^2=0
Wy multiply elements
-12x^2+12x=0
a = -12; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-12)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-12}=\frac{-24}{-24} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-12}=\frac{0}{-24} =0 $
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