If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5x^2=25
We move all terms to the left:
5x^2-(25)=0
a = 5; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·5·(-25)
Δ = 500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{500}=\sqrt{100*5}=\sqrt{100}*\sqrt{5}=10\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{5}}{2*5}=\frac{0-10\sqrt{5}}{10} =-\frac{10\sqrt{5}}{10} =-\sqrt{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{5}}{2*5}=\frac{0+10\sqrt{5}}{10} =\frac{10\sqrt{5}}{10} =\sqrt{5} $
| 4+3+a+2)=16 | | 2y+3+3(5-2y)=16-(2y-3)-2(y-1) | | 7m+m=40 | | -40-7m=-4(m+4) | | 4=6t-10t | | 17=24+y,47 | | x=-646-6x | | 6+4t=−10 | | 294w+7)=3(6+2w) | | F(2)=4x+1/12 | | 4^(3x-1)=3^(x-2) | | 8^5x=7^x-3 | | 4/x+3-2/x-3=5x/x2-9 | | 10+3x=13x-65 | | 21=(2m-1)3 | | (x)=130+52x | | M(t)=130+52t | | 3x-12+1=1 | | 2+-g=5 | | -5+-t=-7 | | x^2=19x+90=0 | | 7x-1=5×+3 | | 12.1+5.5=2(x) | | 12.1+5.5=2x | | 12.2+5.5=2x | | x/2+10°+90°+2x+15°=180° | | 12y-5=3y+31 | | .3*x=x-3000 | | 6-2x/5=1+3/5/x | | 6-2x/5=1+3/5x | | (1500/y)*y=1500 | | 7x+2x+9=5x+37 |