2y+3+3(5-2y)=16-(2y-3)-2(y-1)

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Solution for 2y+3+3(5-2y)=16-(2y-3)-2(y-1) equation: 



2y+3+3(5-2y)=16-(2y-3)-2(y-1)

We move all terms to the left:

2y+3+3(5-2y)-(16-(2y-3)-2(y-1))=0

We add all the numbers together, and all the variables

2y+3(-2y+5)-(16-(2y-3)-2(y-1))+3=0

We multiply parentheses

2y-6y-(16-(2y-3)-2(y-1))+15+3=0



We calculate terms in parentheses: -(16-(2y-3)-2(y-1)), so:

16-(2y-3)-2(y-1)

determiningTheFunctionDomain
-(2y-3)-2(y-1)+16

We multiply parentheses

-(2y-3)-2y+2+16

We get rid of parentheses

-2y-2y+3+2+16

We add all the numbers together, and all the variables

-4y+21

Back to the equation:

-(-4y+21)



We add all the numbers together, and all the variables

-4y-(-4y+21)+18=0

We get rid of parentheses

-4y+4y-21+18=0

We add all the numbers together, and all the variables

-3!=0

There is no solution for this equation

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