# 5x2=14

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## Solution for 5x2=14 equation:

5x^2=14
We move all terms to the left:
5x^2-(14)=0
a = 5; b = 0; c = -14;Δ = b2-4acΔ = 02-4·5·(-14)Δ = 280The delta value is higher than zero, so the equation has two solutionsWe use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$The end solution:
$\sqrt{\Delta}=\sqrt{280}=\sqrt{4*70}=\sqrt{4}*\sqrt{70}=2\sqrt{70}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{70}}{2*5}=\frac{0-2\sqrt{70}}{10} =-\frac{2\sqrt{70}}{10} =-\frac{\sqrt{70}}{5}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{70}}{2*5}=\frac{0+2\sqrt{70}}{10} =\frac{2\sqrt{70}}{10} =\frac{\sqrt{70}}{5}$

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