4(r-3)=2r+7

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Solution for 4(r-3)=2r+7 equation: 



4(r-3)=2r+7

We move all terms to the left:

4(r-3)-(2r+7)=0

We multiply parentheses

4r-(2r+7)-12=0

We get rid of parentheses

4r-2r-7-12=0

We add all the numbers together, and all the variables

2r-19=0

We move all terms containing r to the left, all other terms to the right

2r=19

r=19/2

r=9+1/2

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