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5x^2-55=0
a = 5; b = 0; c = -55;
Δ = b2-4ac
Δ = 02-4·5·(-55)
Δ = 1100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1100}=\sqrt{100*11}=\sqrt{100}*\sqrt{11}=10\sqrt{11}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{11}}{2*5}=\frac{0-10\sqrt{11}}{10} =-\frac{10\sqrt{11}}{10} =-\sqrt{11} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{11}}{2*5}=\frac{0+10\sqrt{11}}{10} =\frac{10\sqrt{11}}{10} =\sqrt{11} $
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