5x2-355=0

Solution for 5x2-355=0 equation:

5x^2-355=0

a = 5; b = 0; c = -355;
Δ = b2-4ac
Δ = 02-4·5·(-355)
Δ = 7100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7100}=\sqrt{100*71}=\sqrt{100}*\sqrt{71}=10\sqrt{71}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{71}}{2*5}=\frac{0-10\sqrt{71}}{10}
=-\frac{10\sqrt{71}}{10}
=-\sqrt{71}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{71}}{2*5}=\frac{0+10\sqrt{71}}{10}
=\frac{10\sqrt{71}}{10}
=\sqrt{71}
$