(x-4)(x-3)=0.5x(x-4)

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Solution for (x-4)(x-3)=0.5x(x-4) equation: 



(x-4)(x-3)=0.5x(x-4)

We move all terms to the left:

(x-4)(x-3)-(0.5x(x-4))=0

We multiply parentheses ..

(+x^2-3x-4x+12)-(0.5x(x-4))=0



We calculate terms in parentheses: -(0.5x(x-4)), so:

0.5x(x-4)

We multiply parentheses

0x^2+0x

We add all the numbers together, and all the variables

x^2+x

Back to the equation:

-(x^2+x)



We get rid of parentheses

x^2-x^2-3x-4x-x+12=0

We add all the numbers together, and all the variables

-8x+12=0

We move all terms containing x to the left, all other terms to the right

-8x=-12

x=-12/-8

x=1+1/2

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