If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5x^2+6x-11=0
a = 5; b = 6; c = -11;
Δ = b2-4ac
Δ = 62-4·5·(-11)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-16}{2*5}=\frac{-22}{10} =-2+1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+16}{2*5}=\frac{10}{10} =1 $
| n-69=12 | | 180=4x-19 | | 2(4x-1)=8x-2* | | 84-21x=34x-26 | | 6x(.25x)x1.5=9 | | 1/4x+16=x+10 | | 1/3(3y+12)=6 | | 2(u+10)—-8=8 | | 32+8a=7(5a-7) | | 3x(4-2x)=5x+9 | | 5n-5(1+7n)=-8+3(1-3n) | | 2x+7/8+x-5/4x=-5/2x | | (4x+1)=(4x+1) | | x2+14x=-40 | | 2x+6-x-14=7+4x | | |x|-7=33 | | 7k+23=86 | | 2x-4-5=4 | | -1(2x+40=-4x+5 | | 4a+4=a+18 | | 6(x-2)=36=10x | | 100x=2500-x^2 | | 90=5x-4 | | 5x2=6125 | | 8(1+8b)=-248 | | -(8m+4)=4m—2(6m+2) | | 2(4y-4)=2(4y−4)=4040 | | 57=-3(4v+1)2v | | 17v2=153 | | 2(w-14)=6 | | 3=z/2-(-2) | | –7p=–6p+5 |