57=-3(4v+1)2v

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Solution for 57=-3(4v+1)2v equation: 



57=-3(4v+1)2v

We move all terms to the left:

57-(-3(4v+1)2v)=0



We calculate terms in parentheses: -(-3(4v+1)2v), so:

-3(4v+1)2v

We multiply parentheses

-24v^2-6v

Back to the equation:

-(-24v^2-6v)



We get rid of parentheses

24v^2+6v+57=0

a = 24; b = 6; c = +57;
Δ = b2-4ac
Δ = 62-4·24·57
Δ = -5436
Delta is less than zero, so there is no solution for the equation

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