5x2+25x-1500=0

Solution for 5x2+25x-1500=0 equation:

5x^2+25x-1500=0

a = 5; b = 25; c = -1500;
Δ = b2-4ac
Δ = 252-4·5·(-1500)
Δ = 30625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{30625}=175$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-175}{2*5}=\frac{-200}{10}
=-20
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+175}{2*5}=\frac{150}{10}
=15
$