10y-50=-5(y-2)

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Solution for 10y-50=-5(y-2) equation: 



10y-50=-5(y-2)

We move all terms to the left:

10y-50-(-5(y-2))=0



We calculate terms in parentheses: -(-5(y-2)), so:

-5(y-2)

We multiply parentheses

-5y+10

Back to the equation:

-(-5y+10)



We get rid of parentheses

10y+5y-10-50=0

We add all the numbers together, and all the variables

15y-60=0

We move all terms containing y to the left, all other terms to the right

15y=60

y=60/15

y=4

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