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5x^2+19=739
We move all terms to the left:
5x^2+19-(739)=0
We add all the numbers together, and all the variables
5x^2-720=0
a = 5; b = 0; c = -720;
Δ = b2-4ac
Δ = 02-4·5·(-720)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{14400}=120$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120}{2*5}=\frac{-120}{10} =-12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120}{2*5}=\frac{120}{10} =12 $
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