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10x^2+32=1722
We move all terms to the left:
10x^2+32-(1722)=0
We add all the numbers together, and all the variables
10x^2-1690=0
a = 10; b = 0; c = -1690;
Δ = b2-4ac
Δ = 02-4·10·(-1690)
Δ = 67600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{67600}=260$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-260}{2*10}=\frac{-260}{20} =-13 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+260}{2*10}=\frac{260}{20} =13 $
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