SIN(3x+10)=COS(2x-20)

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Solution for SIN(3x+10)=COS(2x-20) equation: 



(3S+10)=(2S-20)

We move all terms to the left:

(3S+10)-((2S-20))=0

We get rid of parentheses

3S-((2S-20))+10=0



We calculate terms in parentheses: -((2S-20)), so:

(2S-20)

We get rid of parentheses

2S-20

Back to the equation:

-(2S-20)



We get rid of parentheses

3S-2S+20+10=0

We add all the numbers together, and all the variables

S+30=0

We move all terms containing S to the left, all other terms to the right

S=-30

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