5x2+13x+4=0

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Solution for 5x2+13x+4=0 equation: 



5x^2+13x+4=0

a = 5; b = 13; c = +4;
Δ = b2-4ac
Δ = 132-4·5·4
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{89}}{2*5}=\frac{-13-\sqrt{89}}{10}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{89}}{2*5}=\frac{-13+\sqrt{89}}{10}
$

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