5x/(x+1)=2-5/(x+1)

Solution for 5x/(x+1)=2-5/(x+1) equation:

5x/(x+1)=2-5/(x+1)

We move all terms to the left:

5x/(x+1)-(2-5/(x+1))=0


Domain of the equation: (x+1)!=0

We move all terms containing x to the left, all other terms to the right

x!=-1

x∈R



Domain of the equation: (x+1))!=0

x∈R


We calculate fractions


10x^2/((x+1)*(x+1)))+(-(-5*(x+3))/((x+1)*(x+1)))=0


We calculate terms in parentheses: -(-5*(x+3))/((x+1)*(x+1))), so:

-5*(x+3))/((x+1)*(x+1))

We multiply all the terms by the denominator


-5*(x+3))

We multiply parentheses

-5x-

We add all the numbers together, and all the variables

-5x

Back to the equation:

-(-5x)


We get rid of parentheses

10x^2/((x+1)*(x+1)))+(+5x=0

We multiply all the terms by the denominator


10x^2+5x*((x+1)*(x+1)))+(=0