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2x+5/6x=160
We move all terms to the left:
2x+5/6x-(160)=0
Domain of the equation: 6x!=0We multiply all the terms by the denominator
x!=0/6
x!=0
x∈R
2x*6x-160*6x+5=0
Wy multiply elements
12x^2-960x+5=0
a = 12; b = -960; c = +5;
Δ = b2-4ac
Δ = -9602-4·12·5
Δ = 921360
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{921360}=\sqrt{16*57585}=\sqrt{16}*\sqrt{57585}=4\sqrt{57585}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-960)-4\sqrt{57585}}{2*12}=\frac{960-4\sqrt{57585}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-960)+4\sqrt{57585}}{2*12}=\frac{960+4\sqrt{57585}}{24} $
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