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5x-8=3/2x+6
We move all terms to the left:
5x-8-(3/2x+6)=0
Domain of the equation: 2x+6)!=0We get rid of parentheses
x∈R
5x-3/2x-6-8=0
We multiply all the terms by the denominator
5x*2x-6*2x-8*2x-3=0
Wy multiply elements
10x^2-12x-16x-3=0
We add all the numbers together, and all the variables
10x^2-28x-3=0
a = 10; b = -28; c = -3;
Δ = b2-4ac
Δ = -282-4·10·(-3)
Δ = 904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{904}=\sqrt{4*226}=\sqrt{4}*\sqrt{226}=2\sqrt{226}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-2\sqrt{226}}{2*10}=\frac{28-2\sqrt{226}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+2\sqrt{226}}{2*10}=\frac{28+2\sqrt{226}}{20} $
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