1/5(29x-15)=7x+9

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Solution for 1/5(29x-15)=7x+9 equation: 



1/5(29x-15)=7x+9

We move all terms to the left:

1/5(29x-15)-(7x+9)=0



Domain of the equation: 5(29x-15)!=0

x∈R



We get rid of parentheses

1/5(29x-15)-7x-9=0

We multiply all the terms by the denominator


-7x*5(29x-15)-9*5(29x-15)+1=0

Wy multiply elements

-35x^2(2-45x(2+1=0

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