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5x-6=x(x-10)
We move all terms to the left:
5x-6-(x(x-10))=0
We calculate terms in parentheses: -(x(x-10)), so:We get rid of parentheses
x(x-10)
We multiply parentheses
x^2-10x
Back to the equation:
-(x^2-10x)
-x^2+5x+10x-6=0
We add all the numbers together, and all the variables
-1x^2+15x-6=0
a = -1; b = 15; c = -6;
Δ = b2-4ac
Δ = 152-4·(-1)·(-6)
Δ = 201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{201}}{2*-1}=\frac{-15-\sqrt{201}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{201}}{2*-1}=\frac{-15+\sqrt{201}}{-2} $
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