6x(1+2x)=5(3x-1)-4

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Solution for 6x(1+2x)=5(3x-1)-4 equation: 



6x(1+2x)=5(3x-1)-4

We move all terms to the left:

6x(1+2x)-(5(3x-1)-4)=0

We add all the numbers together, and all the variables

6x(2x+1)-(5(3x-1)-4)=0

We multiply parentheses

12x^2+6x-(5(3x-1)-4)=0



We calculate terms in parentheses: -(5(3x-1)-4), so:

5(3x-1)-4

We multiply parentheses

15x-5-4

We add all the numbers together, and all the variables

15x-9

Back to the equation:

-(15x-9)



We get rid of parentheses

12x^2+6x-15x+9=0

We add all the numbers together, and all the variables

12x^2-9x+9=0

a = 12; b = -9; c = +9;
Δ = b2-4ac
Δ = -92-4·12·9
Δ = -351
Delta is less than zero, so there is no solution for the equation

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