5x-4=1/5+20x

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Solution for 5x-4=1/5+20x equation: 



5x-4=1/5+20x

We move all terms to the left:

5x-4-(1/5+20x)=0



Domain of the equation: 5+20x)!=0

We move all terms containing x to the left, all other terms to the right

20x)!=-5

x!=-5/1

x!=-5

x∈R



We add all the numbers together, and all the variables

5x-(+20x+1/5)-4=0

We get rid of parentheses

5x-20x-4-1/5=0

We multiply all the terms by the denominator


5x*5-20x*5-1-4*5=0

We add all the numbers together, and all the variables

5x*5-20x*5-21=0

Wy multiply elements

25x-100x-21=0

We add all the numbers together, and all the variables

-75x-21=0

We move all terms containing x to the left, all other terms to the right

-75x=21

x=21/-75

x=-7/25

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