3(y-3)-5=-6(-2y+2)-y

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Solution for 3(y-3)-5=-6(-2y+2)-y equation: 



3(y-3)-5=-6(-2y+2)-y

We move all terms to the left:

3(y-3)-5-(-6(-2y+2)-y)=0

We multiply parentheses

3y-(-6(-2y+2)-y)-9-5=0



We calculate terms in parentheses: -(-6(-2y+2)-y), so:

-6(-2y+2)-y

We add all the numbers together, and all the variables

-1y-6(-2y+2)

We multiply parentheses

-1y+12y-12

We add all the numbers together, and all the variables

11y-12

Back to the equation:

-(11y-12)



We add all the numbers together, and all the variables

3y-(11y-12)-14=0

We get rid of parentheses

3y-11y+12-14=0

We add all the numbers together, and all the variables

-8y-2=0

We move all terms containing y to the left, all other terms to the right

-8y=2

y=2/-8

y=-1/4

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