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5x-3=4-1/2x
We move all terms to the left:
5x-3-(4-1/2x)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
5x-(-1/2x+4)-3=0
We get rid of parentheses
5x+1/2x-4-3=0
We multiply all the terms by the denominator
5x*2x-4*2x-3*2x+1=0
Wy multiply elements
10x^2-8x-6x+1=0
We add all the numbers together, and all the variables
10x^2-14x+1=0
a = 10; b = -14; c = +1;
Δ = b2-4ac
Δ = -142-4·10·1
Δ = 156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{156}=\sqrt{4*39}=\sqrt{4}*\sqrt{39}=2\sqrt{39}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{39}}{2*10}=\frac{14-2\sqrt{39}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{39}}{2*10}=\frac{14+2\sqrt{39}}{20} $
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