3x-2=4(1-x)+6

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Solution for 3x-2=4(1-x)+6 equation:



3x-2=4(1-x)+6
We move all terms to the left:
3x-2-(4(1-x)+6)=0
We add all the numbers together, and all the variables
3x-(4(-1x+1)+6)-2=0
We calculate terms in parentheses: -(4(-1x+1)+6), so:
4(-1x+1)+6
We multiply parentheses
-4x+4+6
We add all the numbers together, and all the variables
-4x+10
Back to the equation:
-(-4x+10)
We get rid of parentheses
3x+4x-10-2=0
We add all the numbers together, and all the variables
7x-12=0
We move all terms containing x to the left, all other terms to the right
7x=12
x=12/7
x=1+5/7

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