5x-3(2x-1)+7=2(x+1)-5

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Solution for 5x-3(2x-1)+7=2(x+1)-5 equation: 



5x-3(2x-1)+7=2(x+1)-5

We move all terms to the left:

5x-3(2x-1)+7-(2(x+1)-5)=0

We multiply parentheses

5x-6x-(2(x+1)-5)+3+7=0



We calculate terms in parentheses: -(2(x+1)-5), so:

2(x+1)-5

We multiply parentheses

2x+2-5

We add all the numbers together, and all the variables

2x-3

Back to the equation:

-(2x-3)



We add all the numbers together, and all the variables

-1x-(2x-3)+10=0

We get rid of parentheses

-1x-2x+3+10=0

We add all the numbers together, and all the variables

-3x+13=0

We move all terms containing x to the left, all other terms to the right

-3x=-13

x=-13/-3

x=4+1/3

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