5x-2(2x-4)-8=3(x+2)

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Solution for 5x-2(2x-4)-8=3(x+2) equation: 



5x-2(2x-4)-8=3(x+2)

We move all terms to the left:

5x-2(2x-4)-8-(3(x+2))=0

We multiply parentheses

5x-4x-(3(x+2))+8-8=0



We calculate terms in parentheses: -(3(x+2)), so:

3(x+2)

We multiply parentheses

3x+6

Back to the equation:

-(3x+6)



We add all the numbers together, and all the variables

x-(3x+6)=0

We get rid of parentheses

x-3x-6=0

We add all the numbers together, and all the variables

-2x-6=0

We move all terms containing x to the left, all other terms to the right

-2x=6

x=6/-2

x=-3

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