0.16x+.2(x-2)=0.01(3x-2)

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Solution for 0.16x+.2(x-2)=0.01(3x-2) equation: 



0.16x+.2(x-2)=0.01(3x-2)

We move all terms to the left:

0.16x+.2(x-2)-(0.01(3x-2))=0

We multiply parentheses

0.16x+0.2x-(0.01(3x-2))-0.4=0



We calculate terms in parentheses: -(0.01(3x-2)), so:

0.01(3x-2)

We multiply parentheses

0.03x-0.02

Back to the equation:

-(0.03x-0.02)



We add all the numbers together, and all the variables

0.36x-(0.03x-0.02)-0.4=0

We get rid of parentheses

0.36x-0.03x+0.02-0.4=0

We add all the numbers together, and all the variables

0.33x-0.38=0

We move all terms containing x to the left, all other terms to the right

0.33x=0.38

x=0.38/0.33

x=1+0.05/0.33

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