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5x-13=-4/3x+6
We move all terms to the left:
5x-13-(-4/3x+6)=0
Domain of the equation: 3x+6)!=0We get rid of parentheses
x∈R
5x+4/3x-6-13=0
We multiply all the terms by the denominator
5x*3x-6*3x-13*3x+4=0
Wy multiply elements
15x^2-18x-39x+4=0
We add all the numbers together, and all the variables
15x^2-57x+4=0
a = 15; b = -57; c = +4;
Δ = b2-4ac
Δ = -572-4·15·4
Δ = 3009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-57)-\sqrt{3009}}{2*15}=\frac{57-\sqrt{3009}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-57)+\sqrt{3009}}{2*15}=\frac{57+\sqrt{3009}}{30} $
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