(12+3)+1=n+(3+1)

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Solution for (12+3)+1=n+(3+1) equation:



(12+3)+1=n+(3+1)
We move all terms to the left:
(12+3)+1-(n+(3+1))=0
We add all the numbers together, and all the variables
-(n+4)+1+15=0
We add all the numbers together, and all the variables
-(n+4)+16=0
We get rid of parentheses
-n-4+16=0
We add all the numbers together, and all the variables
-1n+12=0
We move all terms containing n to the left, all other terms to the right
-n=-12
n=-12/-1
n=+12

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