5x-12+7x=4(4x-4)+2

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Solution for 5x-12+7x=4(4x-4)+2 equation: 



5x-12+7x=4(4x-4)+2

We move all terms to the left:

5x-12+7x-(4(4x-4)+2)=0

We add all the numbers together, and all the variables

12x-(4(4x-4)+2)-12=0



We calculate terms in parentheses: -(4(4x-4)+2), so:

4(4x-4)+2

We multiply parentheses

16x-16+2

We add all the numbers together, and all the variables

16x-14

Back to the equation:

-(16x-14)



We get rid of parentheses

12x-16x+14-12=0

We add all the numbers together, and all the variables

-4x+2=0

We move all terms containing x to the left, all other terms to the right

-4x=-2

x=-2/-4

x=1/2

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