5x-1/3(x-4)=4+1/4(2x+3)

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Solution for 5x-1/3(x-4)=4+1/4(2x+3) equation: 



5x-1/3(x-4)=4+1/4(2x+3)

We move all terms to the left:

5x-1/3(x-4)-(4+1/4(2x+3))=0



Domain of the equation: 3(x-4)!=0

x∈R





Domain of the equation: 4(2x+3))!=0

x∈R



We calculate fractions


5x+(-4x2/(3(x-4)*4(2x+3)))+(-3xx/(3(x-4)*4(2x+3)))=0



We calculate terms in parentheses: +(-4x2/(3(x-4)*4(2x+3))), so:

-4x2/(3(x-4)*4(2x+3))

We multiply all the terms by the denominator


-4x2

We add all the numbers together, and all the variables

-4x^2

Back to the equation:

+(-4x^2)





We calculate terms in parentheses: +(-3xx/(3(x-4)*4(2x+3))), so:

-3xx/(3(x-4)*4(2x+3))

We multiply all the terms by the denominator


-3xx

Back to the equation:

+(-3xx)



We get rid of parentheses

-4x^2+5x-3xx=0

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