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38/2x-1=60/4x-26
We move all terms to the left:
38/2x-1-(60/4x-26)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 4x-26)!=0We get rid of parentheses
x∈R
38/2x-60/4x+26-1=0
We calculate fractions
152x/8x^2+(-120x)/8x^2+26-1=0
We add all the numbers together, and all the variables
152x/8x^2+(-120x)/8x^2+25=0
We multiply all the terms by the denominator
152x+(-120x)+25*8x^2=0
Wy multiply elements
200x^2+152x+(-120x)=0
We get rid of parentheses
200x^2+152x-120x=0
We add all the numbers together, and all the variables
200x^2+32x=0
a = 200; b = 32; c = 0;
Δ = b2-4ac
Δ = 322-4·200·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-32}{2*200}=\frac{-64}{400} =-4/25 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+32}{2*200}=\frac{0}{400} =0 $
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