5x-(3x-7)-(4-2x-(6x-3))=10

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Solution for 5x-(3x-7)-(4-2x-(6x-3))=10 equation: 



5x-(3x-7)-(4-2x-(6x-3))=10

We move all terms to the left:

5x-(3x-7)-(4-2x-(6x-3))-(10)=0

We get rid of parentheses

5x-3x-(4-2x-(6x-3))+7-10=0



We calculate terms in parentheses: -(4-2x-(6x-3)), so:

4-2x-(6x-3)

determiningTheFunctionDomain
-2x-(6x-3)+4

We get rid of parentheses

-2x-6x+3+4

We add all the numbers together, and all the variables

-8x+7

Back to the equation:

-(-8x+7)



We add all the numbers together, and all the variables

2x-(-8x+7)-3=0

We get rid of parentheses

2x+8x-7-3=0

We add all the numbers together, and all the variables

10x-10=0

We move all terms containing x to the left, all other terms to the right

10x=10

x=10/10

x=1

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