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X(-2)=X2-4X
We move all terms to the left:
X(-2)-(X2-4X)=0
We add all the numbers together, and all the variables
-(+X^2-4X)+X(-2)=0
We multiply parentheses
-(+X^2-4X)-2X=0
We get rid of parentheses
-X^2+4X-2X=0
We add all the numbers together, and all the variables
-1X^2+2X=0
a = -1; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-1)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-1}=\frac{-4}{-2} =+2 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-1}=\frac{0}{-2} =0 $
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