5x-(2x+2x)=x(3x-5)

Solution for 5x-(2x+2x)=x(3x-5) equation:

5x-(2x+2x)=x(3x-5)

We move all terms to the left:

5x-(2x+2x)-(x(3x-5))=0

We add all the numbers together, and all the variables

5x-(+4x)-(x(3x-5))=0

We get rid of parentheses

5x-4x-(x(3x-5))=0


We calculate terms in parentheses: -(x(3x-5)), so:

x(3x-5)

We multiply parentheses

3x^2-5x

Back to the equation:

-(3x^2-5x)


We add all the numbers together, and all the variables

x-(3x^2-5x)=0

We get rid of parentheses

-3x^2+x+5x=0

We add all the numbers together, and all the variables

-3x^2+6x=0

a = -3; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·(-3)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*-3}=\frac{-12}{-6}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*-3}=\frac{0}{-6}
=0
$