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2/3y+2-1/6y=0
Domain of the equation: 3y!=0
y!=0/3
y!=0
y∈R
Domain of the equation: 6y!=0We calculate fractions
y!=0/6
y!=0
y∈R
12y/18y^2+(-3y)/18y^2+2=0
We multiply all the terms by the denominator
12y+(-3y)+2*18y^2=0
Wy multiply elements
36y^2+12y+(-3y)=0
We get rid of parentheses
36y^2+12y-3y=0
We add all the numbers together, and all the variables
36y^2+9y=0
a = 36; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·36·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*36}=\frac{-18}{72} =-1/4 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*36}=\frac{0}{72} =0 $
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