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5x+6=2(x+6)x=
We move all terms to the left:
5x+6-(2(x+6)x)=0
We calculate terms in parentheses: -(2(x+6)x), so:We get rid of parentheses
2(x+6)x
We multiply parentheses
2x^2+12x
Back to the equation:
-(2x^2+12x)
-2x^2+5x-12x+6=0
We add all the numbers together, and all the variables
-2x^2-7x+6=0
a = -2; b = -7; c = +6;
Δ = b2-4ac
Δ = -72-4·(-2)·6
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{97}}{2*-2}=\frac{7-\sqrt{97}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{97}}{2*-2}=\frac{7+\sqrt{97}}{-4} $
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