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5x+4=3(2x-5)-(x-5)
We move all terms to the left:
5x+4-(3(2x-5)-(x-5))=0
We calculate terms in parentheses: -(3(2x-5)-(x-5)), so:We get rid of parentheses
3(2x-5)-(x-5)
We multiply parentheses
6x-(x-5)-15
We get rid of parentheses
6x-x+5-15
We add all the numbers together, and all the variables
5x-10
Back to the equation:
-(5x-10)
5x-5x+10+4=0
We add all the numbers together, and all the variables
14!=0
There is no solution for this equation
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