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5x+4=2/3x(10-x)
We move all terms to the left:
5x+4-(2/3x(10-x))=0
Domain of the equation: 3x(10-x))!=0We add all the numbers together, and all the variables
x∈R
5x-(2/3x(-1x+10))+4=0
We multiply all the terms by the denominator
5x*3x(-1x+10))-(2+4*3x(-1x+10))=0
Wy multiply elements
15x^2(-+12x(-=0
We use the square of the difference formula
15x^2(-12x(-=0
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