40-19=3(x-2)

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Solution for 40-19=3(x-2) equation: 



40-19=3(x-2)

We move all terms to the left:

40-19-(3(x-2))=0

We add all the numbers together, and all the variables

-(3(x-2))+21=0



We calculate terms in parentheses: -(3(x-2)), so:

3(x-2)

We multiply parentheses

3x-6

Back to the equation:

-(3x-6)



We get rid of parentheses

-3x+6+21=0

We add all the numbers together, and all the variables

-3x+27=0

We move all terms containing x to the left, all other terms to the right

-3x=-27

x=-27/-3

x=+9

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