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5x+3=2(x*2-x+3)-2x*2
We move all terms to the left:
5x+3-(2(x*2-x+3)-2x*2)=0
We add all the numbers together, and all the variables
5x-(2(-1x+x*2+3)-2x*2)+3=0
We calculate terms in parentheses: -(2(-1x+x*2+3)-2x*2), so:We get rid of parentheses
2(-1x+x*2+3)-2x*2
We multiply parentheses
-2x+4x-2x*2+6
Wy multiply elements
-2x+4x-4x+6
We add all the numbers together, and all the variables
-2x+6
Back to the equation:
-(-2x+6)
5x+2x-6+3=0
We add all the numbers together, and all the variables
7x-3=0
We move all terms containing x to the left, all other terms to the right
7x=3
x=3/7
x=3/7
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